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20-4-2012
Vin=2V, Vdd=5V, VTHn=1V, VTHp=-1V, b1= 400mA/V2, b2=200mA/V2, bF3=50 , Vg=0,6V, VT=25mV, RC=100 W, RB=10 KW
Vdd
Vin
Vout
M1
M2
Q3
Vx Vy
Rc
Rb
2 211
2 222
2 1
: 1, 2
4002 1 200
2 2
2005 2 1 400
2 2
200
10
4
0.6
0.6 10000 200 0.6 2 2.6
D in THn
D dd A THp
B D D
C B
out DD C C
y
x y B B
Ipotesi M M saturi
I V V A
I V V V A
I I I A
I I mA
V V R I V
V V
V V R I
ipotesi di saturazione verificat
bm
bm
m
b
m
e
20-4-2012 Vdd
Vin
Vout
M1
M2
Q3
Vx Vy
Rc
Rb
gm2 (-vin)
gm1 vin
vin
gm3 vbe
vout
r
Rb
Rc
p
gm2 vingm3 vy
voutvin
Rb
r
Rc
gm1 vin
vx vy
1 2
3
1 2 3
( )
( )
m m in y
out m C y
outm m m C
in
r g g v v
v g R v
vr g g g R
v
p
p
gm1=400(2-1)=400 mS, gm2=200(5-2-1)=400 mS, gm3= IC3/ VT= 400mS, rp3= b3/ gm3=125W, A V= - 3.2 V
20-4-2012
R1=4 kW, R2=2 kW, R3=2 kW, Vin=0.5 V
1 2 3
2 3 2 3
1 1 2 3
2 20.25
( ) 4 (2 2)
out x
in out out
out
in
V V
V V V V V V
R R R
R RV R R
V R R R R
IR1= 125 mA, IR2= -62,5mA, IR3=-62,5mA, V out= V x= -0.125 V
20-6-2012
Vin1=4V, Vin2=4V, Vdd=5V, VTHn=1V, bA1= bB1= 20mA/V2, bC1= 40mA/V2, bA2= bB2= 40mA/V2, bC2= 80mA/V2, R=20 kW.
Vout
Vdd
RMA1
Vx1
Vin1 Vin2
Vx2
MB1 MC1 MB2MC2
MA2
2 21 11 1 1 1 1
1 1 1
11
2 211 1 1
2 211 1
22
2 2
1
:
2 2
22
202 1 10
2 2
402 1 20
2 2
...
22
20
4
A BDA in x THn DB x THn
in x THn x THn
inx
BDA DB x THn
CDC x THn
inx
DA DB
DC
Ipotesi MOSFET saturi
I V V V I V V
V V V V V
VV V
I I V V A
I V V A
VV V
I I A
I
b b
b mm
b mm
m
2 1
0
60
10
5 20 *60 3,8
R DC DC
C B
out DD R
A
I I I A
I I mA
V V RI K V
ipotesi di saturazione verificate
m
m
b
m
RgmA1(vin1-vx1)
vx1
vout
gmB1gmC1 vx1
gmA2(vin2-vx2)
vx2
gmB2gmC2 vx2
11 1 1
1
11 1
1 1
22 2
2 2
1 1 2 2
1 21 1 2
1 1 2 2
1 1 1
1 1 1
( )
( )
20 *40 0,82
mAx in x
mB
mAx in
mA mB
mAx in
mA mB
out mC x mC x
mA mAout mC in in
mA mB mA mB
out mC mA mC
in mA mB
gv v v
g
gv v
g g
gv v
g g
v R g v g v
g gv R g v v
g g g g
v g g gR R k
v g gm
gmA1= gmB1=20(2-1)=20 mS, gmC1=40(2-1)=40 mS, gmA2= gmB2=40(2-1)=40 mS, gmC2=80(2-1)=80 mS, goA1= goB1= goC1= goA2= goB2= goC2=0
Vout
Vdd
RMA1
Vx1
Vin1 Vin2
Vx2
MB1 MC1 MB2MC2
MA2
20-6-2012
RC=10 k W, RB=400 k W, RE=2 k W, RC=10 k W, VCC=5 V, Vin=1 V, VBE=0,6 V, b=100
-+
Vout
RE
IR
Vin
RB
VCC
RC
VBVC
VE
0
0,6 1 0,6 0,41
400 400
100
(1 ) 101
5 10 *100 4
2 *101 0,202
0,6 1 0,6 0,41
400 400
E
in BE E inB
B B
C B
R E B
C CC C C
E out E E
out E E
in BE E inB
B B
C
V V
V V V VI A
R R K K
I I A
I I I A
V V R I K V
V V R I
V R I K V
V V V VI A
R R K K
I
m
b m
b m
m
m
m
b
100
(1 ) 101
5 10 *100 4
0,6(1 ) (1 )
(1 )
B
R E B
C CC C C
inout E E E B E
B
Ev
B
I A
I I I A
V V R I K V
VV R I R I R
R
RA
R
m
b m
m
b b
b
12-9-2012
Vin=3V, Vdd=5V, Vcc=5V, VT=25mV, b2= 50 , R B=100 kW, R C=2 kW, VTHn=1V, b1=200mA/V2, R=20 kW
VVV 6,02 g
AKR
VVI
B
inB m24
100
6,0322
mAAII BC 2,124*50222 mb
VIRVV CCcc 6,22,1*253
AVVI thnD mb
25616,21002
22
31
1
VRIVV Dddout 12,012,55256,0*2051
R
VVVVVVI outddoutoutthnD
2
2
311 b VVout 89,0 AID m5,2051
M1 sat, Q2 normale diretta
Non in saturazione ma triodo, riprendo il circuito nellipotesi di triodo
V2
RB
VCC
RC
V3
Vout
R
Vdd
Q2M1
Vin
SVg outm mb 17889,0*200)(11
SVVVg outthno mb 142)89,06,1(*200)( 311
mSm
m
V
Ig
T
cm 48
25
2,12 W k
mgr
m
042,148
50
2
22
bp
Rgm2 v2
v2 vout
vin
gm1 v3
RB v3
RCrp go1
in
B
vrR
rv
2
22
p
p
in
B
mBmB vrR
rgRvgRv
2
22223
p
p
in
B
mBmomoout vrR
rgRgrRvgrRv
2
2211311 )||()||(
p
p
918,0042,1100
042,1482178,0)
1142,0*20
20()
1(
2
221
1
kk
kmkm
k
rR
rgRg
Rg
RA
B
mCm
o
v
p
p
12-9-2012 R1= R3= R5=10 k W, R2= R4= R6=20 k W, Vin1=1 V, Vin2=1 V
R4
R3-+
Vout
R6 R5
Vin1
Vin2
R2
R1
-+ VA
VB
VC
VVVR
RRV ininA 33 22
1
21
CBA VVV
3
1
4 R
VV
R
VV CinCout
1
3
4
3
431
3
4 )( inCCinCout VR
R
R
RRVVV
R
RVV
1
3
4
1
21
3
432 ininout V
R
R
R
RR
R
RRVV
VVVVVV ininininout 42610
20
10
2010
10
20101212
14-11-2012
Vin=3V, Vdd=5V, VTHn=1V, VTHp=-1V, I0 =100mA, b1=b2=b3=200mA/V2, b4=400mA/V2.
VxVout
VinM1
M4
M2
I0
M3
VDD
M1 M2 M3 M4 sat
2 21
1 100 5 3 1 1002
D DD in thpI V V V Ab
m
2 3 200D DI I Am
2
2
22,414Dx thn
IV V V
b 4
4
23Dout DD thp
IV V V V
b
1 1( ) 200m DD in thpg V V V Sb m 2 3 2( ) 282,8m m x thng g V V Sb m
4 4( ) 400m DD out thpg V V V Sb m 1 2 3 40o o o og g g g
gm2
gm4
gm1 (-vin)
vx
gm3 vx
vout
1 3
2 4
m mout in
m m
g gv v
g g
0,5vA
VxVout
VinM1
M4
M2
I0
M3
VDD
14-11-2012 R1= R2= R3=10 k W, R4= R5= R6 k W, VA=1 V, VB=2 V
-+
VzVAR1
R2
-+
VoutR3
R4
-+
R5
VB
Vx
Vy
Vk
2 1
2 2
1 1
4 4 2 2
3 3 1 1
1 3
1 2 4 6
y B A B
y B A
out z B A A B
V V V V
R R
R RV V V V
R R
R R R RV V V V V V V
R R R R